1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 | class PrimeNo{ public static void main(String args[]){ int num = Integer.parseInt(args[0]); int flag=0; for(int i=2;i<num;i++){ if(num%i==0) { System.out.println(num+" is not a Prime Number"); flag = 1; break; } } if(flag==0) System.out.println(num+" is a Prime Number"); } } |
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33 Responses to “Java program to Find whether number is Prime or Not”
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import java.util.*;
class prime_number
{
static Scanner sc = new Scanner (System.in);
public static void main()
{
System.out.print(“Enter A Number : “);
int n=sc.nextInt();
if(n==2)
{
System.out.println(“\n2 is a prime number”);
}
for(int i=2;i<n;i++)
{
if(n%i==0)
{
System.out.print("\n"+n+" is not a prime number");
break;
}
else
{
System.out.print("\n"+n+" is a prime number");
break;
}
}
}
}
the for loop should be continued only till n/2, because a number after this cannot divide n.
Yea , but it wont’s work for 3 and 5 . Check it.
why you will use scanner object
import java.util.*;
import java.io.*;
public class one
{
public static void main(String args[])
{
int num;
int flag=0;
System.out.println(“Enter an integer to check ?”);
Scanner in = new Scanner(System.in);
num = in.nextInt();
for(int i=2;i<num;i++){
if(num%i==0)
{
System.out.println(num+" is not a Prime Number");
flag = 1;
break;
}
}
if(flag==0)
System.out.println(num+" is a Prime Number");
}
}
What is the use of flag here?
why did you use the flag .why did you assign 0 and 1 in the flag.it is only comes under true or false statement.
In first 2 is considered as non prime no…!
wertyuiko;
nm,.ertyui
c j h j u j d
very bad site
all use less programs