C++ program to calculate a to the power b without using power function

7 Responses to “C++ program to calculate a to the power b without using power function”

1. dynamoblaze says:

   June 25, 2011 at 5:13 pm

   Sir, this gives a^b+1
2. swati parmar says:

   June 6, 2012 at 12:18 am

   #include
   #include
   void main()
   {
   int n,i,c;
   clrscr();
   printf(“\nEnter a number: “);
   scanf(“%d”,&n);
   for(i=1;i<=n ;i++)
   {
   c=n*n;
   }
   printf("\npower of a number is: %d",c);
   getch();
   }
3. Rahul says:

   June 19, 2012 at 12:29 am

   #include
   #include

   class power
   {
   int base,exp,i,temp;
   public:
   void get();
   void cal();
   void dis();
   power()
   {
   temp=1;
   }
   };

   void power::get()
   {
   cout<>base>>exp;
   }
   void power::cal()
   {
   for(i=1;i<=exp;i++)
   {
   temp=temp*base;
   }
   }
   void power::dis()
   {
   cout<<"Calculated="<<temp;
   }
   void main()
   {
   clrscr();
   power p;
   p.get();
   p.cal();
   p.dis();
   getch();
   }
4. Mani says:

   October 11, 2012 at 5:10 am

   Above program gives wrong answers as well as they occupy high memory any more time to type the simple program is
   # include
   void main()
   {
   int a;
   cout<>a;
   cout<<"\n power of "<<a<<" is "<<a*a;
   }
5. Mani says:

   October 11, 2012 at 5:17 am

   SORRY GUYS I MISTAKED IN ABOVE PROGRAM THE CORRECT CODE IS HERE
   #include
   void main()
   {
   int a;
   cin>>a;
   cout<<"\n power of "<<a<<" is
   "<<a*a;
   }
6. aarthy ravichandran says:

   February 16, 2013 at 6:26 pm

   thanks
7. Priyam Gaurav says:

   March 5, 2013 at 10:21 pm

   This problem can be solved by applying different methods.
   1st Method:

   #include
   #include
   void main()
   {
   int a,b,c,i;
   clrscr;
   printf(“Enter the base: “);
   scanf(“%d”,&a);
   printf(“Enter the power: “);
   scanf(“%d”,&b);
   c=a;
   for(i=1;i<b;i++)
   {
   c=c*a;
   }
   printf("Result = %d",c);
   getch();
   }

   2nd Method:

   #include
   #include
   void power(int a, int b);
   void main()
   {
   int a,b;
   clrscr();
   printf(“Enter the base: “);
   scanf(“%d”,&a);
   printf(“Enter the power: “);
   scanf(“%d”,&b);
   power(a,b);
   getch();
   }
   void power(int a, int b)
   {
   int c;
   c=a;
   for(i=1;i<b;i++)
   {
   c=c*a;
   }
   printf("Result = %d",c);
   }

   There are so many different methods to solve this problem.

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