Palindrome checking using function overloading

Wednesday, April 17th, 2013
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#include "iostream"
using namespace std;
#include "conio.h"
#include "string.h"
class func
{
	public:
		void pal(int );
		void pal(char c[]);
};
void func :: pal(int n)
{
	int n1,sum,a;
	n1=n;
	sum=0;
 
	do
	{
		sum=sum*10;
		a=n%10;
		sum=sum+a;
		n=n/10;
	}while(n>0);
	if(sum==n1)
		cout<<"\n it is Palindrom";
	else
		cout<<"\n it is not a palindrom";
 
}
void func :: pal(char c[])
{
	int l=strlen(c);
	char b[10];
	int i,j;
	for(i=0,j=l-1;i<l;i++,j–)
	{
		b[i]=c[j];
	}
	b[i]='';
	if(strcmp(c,b)==0)
	{cout<<"\nThe entered text is palindrome";
	}
	else
	{cout<<"\n the entered text is not a palindrome";
	}
}
int main()
{
	char c[10];
	int k,r,v;
	func p;
	do
	{
		cout<<"palindrome"<<endl;
		cout<<"1.for interger"<<endl;
		cout<<"2.for character"<<endl;
		cout<<"enter the choice\n"<<endl;
		cin>>r;
		switch(r)
		{
			case 1:
				cout<<"Enter the number";
				cin>>k;
				p.pal(k);
				break;
 
			case 2:
				cout<<"\nEnter the string to be checked"<<endl;
				cin>>c;
				p.pal(c);
				break;
		}
		cout<<"\ndo you want to continue? (1/0)"<<endl;
		cin>>v;
	}while(v==1);
	getch();
}

Author Name :
sathish kumar

Total : 0 Comment


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