Comments on: To reverse the given string using pointer

By: kulbhushan

kulbhushan — Sat, 31 Mar 2012 02:45:37 +0000

and *(str1)= *(str1 + r);

By: kulbhushan

kulbhushan — Sat, 31 Mar 2012 02:42:08 +0000

IN the above program one thing i think is missing again come back to sting. if ” THis is a string”. in the above program it will be only “siht” and the loop will not come back. if we do one more codition like.
while (*(str1) != NULL)
{
while (*(str1+len) != ‘ ‘)
len++
for(i=len-1; i>=0; i–)
{
*(str2+r) = *(str1+i);
r++;
}
*(str2+r) = ”;
}

By: sathyaa

sathyaa — Fri, 24 Feb 2012 10:15:52 +0000

#include
#include
#include
void main()
{
char *str,temp;
int i,j;
printf(“\n Enter the string: “);
scanf(“%s”,str);
for(i=0,j=strlen(str)-1;i<=j;i++,j–){
temp=*(str+i);
*(str+i)=*(str+j);
*(str+j)=temp;
}
printf("%s",str);
getch();
}

By: Gaurav Sharma

Gaurav Sharma — Mon, 01 Aug 2011 06:30:47 +0000

correction in above code is:
while( *(str+len) != ” ) len++;

By: Gaurav Sharma

Gaurav Sharma — Mon, 01 Aug 2011 06:11:27 +0000

void main(void)
{
uchar *str “ABCDE”;
uchar len;
uchar newidex = 0;

len=0;
while( *str != ” ) len++;

str = revstr(str, len, newidex);
PRINT(str);
}

uint* revstr(uchar *str, uchar len, uchar &index)
{
uchar *b;

if(len==0)
{
return b;
}
else
{
b[index++] = str[len];
revstr( str, len-1, index );
}
}

By: esha

esha — Mon, 02 May 2011 05:48:30 +0000

char *s1;
gets(s1);

this is not correct as s1 is not initialized. its giving segmentation fault.

By: kamal

kamal — Sat, 24 Jan 2009 05:18:26 +0000

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so please send me full details
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