# To check whether the given string is palindrome-method 2

Here is  another program, advanced version of the previous program, to check if the entered string is a palindrome. Palindrome is a string segment, which reads same from both the directions. The same method is implemented here in the program also.

Logic :  The given string is referred by two names, where one is traced by the SOL (Start Of Line) and the other is traced from EOL (End Of Line). In every iteration, the condition is checked, if both the characters are the same. If so, sets a flag, “pal” as true (i.e. 1), and hence prints out the result.

The problem can also solved in another method, where we check  by reversing the string and then comparing.

#include<stdio.h>
#include<conio.h>
int stpal(char str);
void main()
{
char str;
int pal;
clrscr();
printf(“\n\n\t ENTER A STRING…: “);
gets(str);
pal = stpal(str);
if(pal)
printf(“\n\t THE ENTERED STRING IS A PALINDROME”);
else
printf(“\n\t THE ENTERED STRING IS NOT A PALINDROME”);
getch();
}
int stpal(char str)
{
int i = 0, len = 0, pal = 1;
while(str[len]!=’\0′)
len++;
len–;
for(i=0; i<len/2; i++)
{
if(str[i] == str[len-i])
pal = 1;
else
{
pal = 0;
break;
}
}
return pal;
}

### 13 Responses to “To check whether the given string is palindrome-method 2”

1. It works fine but it is case sensitive. How to solve that?

2. THIS THING ALSO WORKS !! EASILY UNDERSTANDABLE !!!

#include
#include
int main()
{
int i,j,check=0;
char str;

printf(“ENTER A STRING:\n”);
gets(str);
for(j=0;str[j]!=”;j++);
j=j-1;
i=0;
while(i<=j)
{
if(str[i]==str[j])
{
i=i+1;
j=j-1;
check=1;
}
else
{
check=0;
break;
}
}

if(check==1)
printf("PALINDROME:");
else
printf("NOT A PALINDROME\n");

getch();

}

3. i couldnt understand ur 9th number line// for(j=0;str[j]!=”;j++);
can u pls explain?

4. i couldn’t understand the following part:
for(j=0;str[j]!=” “;j++)
j=j–;
i=0

5. last program is working.easy to enderstand

6. 9TH LINE IS USED FOR CALCULATING THE LENGTH OF THE STRING..

7. Is it raptor compatible ???

8. Mahesh kumar dewat

#include
#include
#include
void main(void)
{
int i,len,halflen,flag=1;
char str;
clrscr();
printf(“Enter a string:\n”);
gets(str);
len=strlen(str);
halflen=len/2;
for(i=0;i<halflen;i++)
{
if(str[i]!=str[i+halflen])
flag=0;
break;

}
if(flag)
printf("It is a Palindrome.");
else
printf("It is not a Palindrome.");
getch();
}

9. Mahesh kumar dewat

#include
main()
{
char a,b;
printf(“enter a string”);
scanf(“%s”,&a);
strcpy(b,a);//copies string a to b
strrev(b);//reverses string b
if(strcmp(a,b)==0)//compares if the original and reverse strings are same
printf(“\n%s is a palindrome”,a);
else
printf(“\n%s is not a palindrome”,a);
return 0;
}

10. fuck u man u r wrong…………….both eg are wrong.

11. definitely this will work…..thanks to mahesh kumar dewat.

#include
#include//this headel file is important
main()
{
char a;
char b;
printf(“enter a string”);
gets(a);
strcpy(b,a);//copies string a to b
strrev(b);//reverses string b
if(strcmp(a,b)==0)//compares if the original and reverse strings are same
printf(“\n%s is a palindrome”,a);
else
printf(“\n%s is not a palindrome”,a);
return 0;
}

12. You need to include the header file to get the desired output!#include
#include
#include
main()
{
char a;
char b;
printf(“enter a string”);
gets(a);
strcpy(b,a);//copies string a to b
strrev(b);//reverses string b
if(strcmp(a,b)==0)//compares if the original and reverse strings are same
printf(“\n%s is a palindrome”,a);
else
printf(“\n%s is not a palindrome”,a);
return 0;
}

13. @ Kaushik

#include
#include

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