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Program to find out whether a entered number is divisible by 3 and 5 or not

Friday, October 7th, 2011

This program find out whether a entered number is divisible by 3 and 5 or not.

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#include "conio.h"
#include "stdio.h"
 
void main()
{
  int num;
  printf("\nEnter a number ");
  scanf("%d",&num);
  if(num%3==0)
  {
    if(num%5==0)
    {
      printf("\nThe number %d is divisible by 3 and 5");
    }
    else
    {
      printf("\nThe number %d is divisible by 3 but not by 5");
    }
  }
  else
  {
    printf("\nThe number %d is niether divisible by 3 nor by 5");
  }
getch();
}

Output:

Enter a number 21
 
Number is divisible by 3 but not by 5
Avatar of chitra

Author Name :
chitra

Total : 1 Comment

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One Response to “Program to find out whether a entered number is divisible by 3 and 5 or not”

  1. k v swaroop says:
    June 19, 2012 at 11:14 am

    #include

    void main()
    {
    int num;
    printf(“\nEnter a number “);
    scanf(“%d”,&num);
    if(num%3==0)
    {
    if(num%5==0)
    {
    printf(“\nThe number %d is divisible by 3 and 5\n”,num);
    }
    else
    {
    printf(“\nThe number %d is divisible by 3 but not by 5\n”,num);
    }
    }
    else
    {
    if(num%5==0)
    “tdiv.c” 31 lines, 507 characters

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