This program find out whether a entered number is divisible by 3 and 5 or not.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 | #include "conio.h" #include "stdio.h" void main() { int num; printf("\nEnter a number "); scanf("%d",&num); if(num%3==0) { if(num%5==0) { printf("\nThe number %d is divisible by 3 and 5"); } else { printf("\nThe number %d is divisible by 3 but not by 5"); } } else { printf("\nThe number %d is niether divisible by 3 nor by 5"); } getch(); } |

**Output:**

Enter a number 21 Number is divisible by 3 but not by 5 |

#include

void main()

{

int num;

printf(“\nEnter a number “);

scanf(“%d”,&num);

if(num%3==0)

{

if(num%5==0)

{

printf(“\nThe number %d is divisible by 3 and 5\n”,num);

}

else

{

printf(“\nThe number %d is divisible by 3 but not by 5\n”,num);

}

}

else

{

if(num%5==0)

“tdiv.c” 31 lines, 507 characters

sir how can I make a program of that series:

1-2+3-4+5-6…..n terms

a program in turbo c that accepts 20 numbers then display how many numbers are odd, even, and how many numbers are divisible by 3

write a java to find no. is divisible by 3 if it is then write c, also if it is divusible by 5 then write m and if both write cm

Condition take no. of range from 1-100

how i answer this question in c program

“write a C program to get input in an array and add the numbers divisible by 11 and 46 .

plz answer this question tomorrow the last day for submission , plz plz plz

kkl;

NEED TO LEARN MORE ON C PROGRAMMING

Q:- WAP to count how many numbers that’s help 10 is dividable.

if there is 15 divisible to both

how could i display the number divisible by 3 0r 5 but not by both

#include

int main()

{

int num;

printf(“Enter a number”);

scanf(“%d”,&num);

if((num % 3 == 0) && (num % 5 == 0))

{

printf(“num is divisible by 3 and 5″);

}

else

{

printf(” num is not divisible by 3 and 5″);

}

return 0;

}