Program to accept five numbers and display the sum of even numbers and product of odd numbers

Here is the program which accepts five numbers and display the sum of even numbers and product of odd numbers.

```#include "conio.h"
#include "stdio.h"

void main()
{
int n,sum=0,mul=1,i;
printf("\nEnter numbers :\n");
for(i=0;i<5;i++)
{
scanf("%d",&n);
if(n%2==0)
sum=sum+n;
else
mul=mul*n;
}
printf("\nThe sum of even numbers is : %d",sum);
printf("\nThe multiplication of odd numbers is : %d",mul);
getch();
}
```

Output:

```Enter numbers : 4 7 18 23 19   The sum of even numbers is : 22 The multiplication of odd numbers is : 3059```

3 Responses to “Program to accept five numbers and display the sum of even numbers and product of odd numbers”

1. please i do not know what this expression mean: if ( n%2==0)

2. it means that the remainder obtain is 0 when number n is divided by 2

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