# program to accept ten numbers from the user and display the lowest one

This program accepts ten numbers from the user and display the lowest one,

```1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 #include "conio.h" #include "stdio.h"   void main() { int num[10],low,i=0,j=1; printf("\nPlease provide 10 numbers to find lowest one "); for(;i<10;i++,j++) { printf("\nEnter number %d : ",j); scanf("%d",&num[i]); } low=num[0]; i=0,j=1; //finding greatest number for(;inum[i+1]) { low=num[i+1]; } } //displaying lowest value printf("\nThe lowest number is : %d",low); getch(); }```

Output:

```Please provide 10 numbers to find lowest one Enter number 1 : 45 Enter number 2 : 63 Enter number 3 : 85 Enter number 4 : 77 Enter number 5 : 21 Enter number 6 : 68 Enter number 7 : 79 Enter number 8 : 82 Enter number 9 : 101 Enter number 10 : 22 The lowest number is : 21```

### 3 Responses to “program to accept ten numbers from the user and display the lowest one”

1. #include
#include

void sort(int a[],int n)
{
int i,j;
for(i=1;i<n;i++)
{
for(j=0;ja[j+1])
{
//swap(a[j],a[j+1]);
a[j]=a[j]^a[j+1];
a[j+1]=a[j]^a[j+1];
a[j]=a[j]^a[j+1];
}
}
}
}
int main()
{
int i,n;
int a[10];
printf(“Enter the number \n”);
for(i=0;i<10;i++)
{
scanf("%d",&a[i]);
}
sort(a,10);

printf("\nsmallest number among the number which u entered is – %d",a[0]);

printf("\n\n") ;

system("pause");
return 0;
}