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Program to calculate a simple interest

chitra — Mon, 17 Oct 2011 10:14:53 +0000

Here is the program to calculate a simple interest

#include "stdio.h"
#include "conio.h"
 
void main()
{
  float principal,rate,time;
  float simpleInterest;
  printf("\nEnter the principal amount ");
  scanf("%f",&principal);
  printf("\nEnter the rate of interest ");
  scanf("%f",&rate);
  printf("\nEnter the time duration ");
  scanf("%f",&time);
  simpleInterest=(principal*rate*time)/100;
  printf("\nThe simple interest is %f",simpleInterest);
getch();
}

Output:

Enter the principal amount 50000
Enter the rate of interest 5
Enter the time duration 2
 
The simple interest is 5000

Program to calculates the area of a rectangle

chitra — Mon, 17 Oct 2011 08:59:20 +0000

Here is the program to calculates the area of a rectangle,

#include "stdio.h"
#include "conio.h"
 
void main()
{
  int w,h;
  int area;
  printf("\nEnter the width of the rectangle ");
  scanf("%d",&w);
  printf("\nEnter the height of the rectangle ");
  scanf("%d",&h);
  area=w*h;
  printf("\nThe area of a rectangle is %d",area);
getch();
}

Output:

Enter the width of the rectangle 8
 
Enter the height of the rectangle 6
 
The area of a rectangle is 48

Program to accept five numbers and display the sum of even numbers and product of odd numbers

chitra — Fri, 14 Oct 2011 10:40:47 +0000

Here is the program which accepts five numbers and display the sum of even numbers and product of odd numbers.

#include "conio.h"
#include "stdio.h"

void main()
{
  int n,sum=0,mul=1,i;
  printf("\nEnter numbers :\n");
  for(i=0;i<5;i++)
  {
  scanf("%d",&n);
  if(n%2==0)
    sum=sum+n;
  else
    mul=mul*n;
  }
  printf("\nThe sum of even numbers is : %d",sum);
  printf("\nThe multiplication of odd numbers is : %d",mul);
getch();
}

Output:

Enter numbers :
4
7
18
23
19
 
The sum of even numbers is : 22
The multiplication of odd numbers is : 3059

Program to check the occurence of digit in a given number

chitra — Fri, 14 Oct 2011 10:34:46 +0000

This program checks the occurrence of digit 5 in a given number.

#include "conio.h"
#include "stdio.h"
 
void main()
{
  int num,i,n,k;
  printf("\nEnter a number : ");
  scanf("%d",&num);
  n=num;
  i=0;
  while(n!=0)
  {
  k=n%10;
  n=n/10;
  if(k==5)
  {
  i++;
  }
  }
  printf("\nThe occurrence of 5 is %d times",i);
getch();
}

Output:

Enter a number : 21353
The occurrence of 5 is 1 times

Program to find out the sum of first n numbers

chitra — Fri, 14 Oct 2011 10:25:54 +0000

Here is the program to find out the sum of first n numbers.

#include "conio.h"
#include "stdio.h"
 
void main()
{
  int i=0,num,sum=0;
clrscr();  printf("\nEnter a number : ");
  scanf("%d",&amp;num);
  for(;i&lt;num;i++)
  {
  sum=sum+i;
  }
  printf(&quot;\n The sum of numbers = %d&quot;,sum);
getch();
}

Output:

Enter a number : 15
 
 The sum of numbers = 105

Program to generate a table of a given input number

chitra — Fri, 14 Oct 2011 09:47:36 +0000

Here is the program which generates a table of a given input number.

#include "conio.h"
#include "stdio.h"
 
void main()
{
  int num,result,i=1;
  printf("\nEnter a number to generate the table : ");
  scanf("%d",&num);
  printf("\nThe table of %d is given below",num);
  while(i<=10)
  {
  result=num*i;
  printf("\n\t %d * %d = %d",num,i,result);
  i++;
  }
getch();
}

Output

Enter a number to generate the table : 3
The table of 3 is given below
	3 * 1 = 3
	3 * 2 = 6
	3 * 3 = 9
	3 * 4 = 12
	3 * 5 = 15
	3 * 6 = 18
	3 * 7 = 21
	3 * 8 = 24
	3 * 9 = 27
	3 * 10 = 30

Program to check a triangle is a equilateral, isosceles or scalene

chitra — Thu, 13 Oct 2011 06:29:00 +0000

Here is the program to check a triangle is equilateral, isosceles or scalene.

#include "conio.h"
#include "stdio.h"
 
void main()
{
  int x,y,z;
  printf("\nEnter the sides of a triangle");
  scanf("%d %d %d",&x,&y,&z);
  if((x==y) && (y==z))
  {
  printf("\nThe triangle is equilateral");
  } 
  else if((x==z) || (y==z) || (x==y))
  {
  printf("\nThe triangle is isoseles");
  }
  else
  {
  printf("\nThe triangle is scalene");
  }
getch();
}

Output:

Enter the sides of a triangle
12
10
12
 
The triangle is isoseles

Program to accept a character and check whether entered character is vowel or not using switch statement

chitra — Fri, 07 Oct 2011 13:32:04 +0000

This program accepts a character and check whether entered character is vowel or not using switch statement.

#include "conio.h"
#include "stdio.h"
 
void main()
{
  char ch;
  printf("\nEnter a charecter to check ");
  scanf("%c",&ch);
  switch(ch)
  {
  case 'a':
	 printf("\nThe entered charecter %c is a vowel",ch);
	 break;
  case 'e':
	 printf("\nThe entered charecter %c is a vowel",ch);
	 break;
  case 'i':
	 printf("\nThe entered charecter %c is a vowel",ch);
	 break;
  case 'o':
	 printf("\nThe entered charecter %c is a vowel",ch);
	 break;
  case 'u':
	 printf("\nThe entered charecter %c is a vowel",ch);
	 break;
  default:
	 printf("\nThe entered is a consonant");
  }
getch();
}

Output:

Enter a charecter to check i
The entered charecter i is a vowel

Program to find out whether a entered number is divisible by 3 and 5 or not

chitra — Fri, 07 Oct 2011 13:08:54 +0000

This program find out whether a entered number is divisible by 3 and 5 or not.

#include "conio.h"
#include "stdio.h"
 
void main()
{
  int num;
  printf("\nEnter a number ");
  scanf("%d",&num);
  if(num%3==0)
  {
    if(num%5==0)
    {
      printf("\nThe number %d is divisible by 3 and 5");
    }
    else
    {
      printf("\nThe number %d is divisible by 3 but not by 5");
    }
  }
  else
  {
    printf("\nThe number %d is niether divisible by 3 nor by 5");
  }
getch();
}

Output:

Enter a number 21
 
Number is divisible by 3 but not by 5

Program to accept a list of numbers and display it in reverse order using function concept

chitra — Fri, 07 Oct 2011 12:34:58 +0000

This program accepts a list of numbers and displays it in reverse order using function concept.

#include "stdio.h"
#include "conio.h"
 
int a[5],b[5];
 
void accept()
{
   int j;
   printf("Enter the list \n");
   for(j=0;j=0;j--,i++)
   {
     b[i]=a[j];
   }
}
 
void display()
{
   int j;
   printf("The list in reverse is \n");
   for(j=0;j<5;j++)
   printf("%d ",b[j]);
   printf("\n");
}
 
void main()
{
   accept();
   reverse();
   display();
getch();
}

Output:

Enter the list
5
4
3
2
1
The list in reverse is
1 2 3 4 5